A geometry problem by Kaleem Kħặŋ

The four gray quarter-circles make one circle with area $A_g=\pi9^2$

The four white half-circles make two circles with area $A_w=2\times\pi\left(\frac92\right)^2$

Total area is $A_g-A_w=\pi\left(81-2\times\left(\frac92\right)^2\right)\approx\boxed{127.25}$