Volume when Area...

Geometry Level 2

The volume of a rectangular solid each of whose side, front, and bottom faces are 12 12 sq. in., 8 8 sq. in., and 6 6 sq. in. respectively is:

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576 cu.in 24 cu. in 104 cu. in 9 cu. in

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Soumo Mukherjee by Soumo Mukherjee , 25, India

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4 solutions

Mehdi Ali
Dec 5, 2014

simply use formula

2 Helpful 0 Interesting 0 Brilliant 0 Confused
Soumo Mukherjee
Nov 2, 2014

let L, B, H be length width and height respectively ;

then,

∴ L H = 12 a n d H W = 8 a n d L W = 6 V 2 = ( L W H ) 2 = 4 2 6 2 o r V = 24 \therefore \quad LH=12\\ and\quad HW=8\\ and\quad LW=6\\ \\ { V }^{ 2 }={ (LWH) }^{ 2 }={ 4 }^{ 2 }{ 6 }^{ 2 }\\ or\quad V=24

2 Helpful 0 Interesting 0 Brilliant 0 Confused

it is correct

Lingaiah Vallakatla - 6 years, 6 months ago

sqare of volume= suare of abc, = ab* bc* ca =12 * 8 * 6 

      therefore  volume = 24 ,  where the measures of cuboid is  a*b*c
1 Helpful 0 Interesting 0 Brilliant 0 Confused
Prakash Suthar
Nov 2, 2014

side face area=height length=12 front face area=height width=8 bottom face area=width length=6 hence, height=4, width=2, length=3 volume of cube=height width*length =4 * 2 * 3=24 cubic inch

1 Helpful 0 Interesting 0 Brilliant 0 Confused

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