A number theory problem by A Former Brilliant Member

The sum of 2 positive integers a a and b b is 52, and their lowest common multiple is 168.

Find the value of a b |a-b| .


The answer is 4.

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1 solution

Tom Engelsman
Dec 27, 2019

Taking 168 = 2 3 3 1 7 1 168 = 2^{3}3^{1}7^{1} , it has positive integer divisors: 1 , 2 , 3 , 4 , 6 , 7 , 8 , 12 , 14 , 21 , 24 , 28 , 42 , 56 , 84 , 168. 1, 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, 168. Of these divisors, 24 + 28 = 52 24 + 28 = 52 . Hence 24 28 = 4 . |24-28| = \boxed{4}.

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