A classical mechanics problem by nitin sachan

A body of mass 5kg is moving with a momentum of 10kg m\s. A force of 0.2N acts on it in the same direction for 10 sec. Find increas in K.E


The answer is 4.4.

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1 solution

Yo Ma
Aug 26, 2014

F = Δ p Δ t , s o Δ p = F Δ t . T h i s m e a n s t h a t p f = 12 m s . K n o w i n g t h a t Δ K E = p f 2 p i 2 2 m , Δ K E = 144 100 2 5 = 4.4 J F\quad =\quad \frac { \Delta p }{ \Delta t } ,\quad so\quad \Delta p\quad =F*\Delta t.\quad This\quad means\quad that\quad { p }_{ f }\quad =\quad 12\frac { m }{ s } .\quad Knowing\quad that\quad \Delta KE\quad =\quad \frac { { p }_{ f }^{ 2 }-{ p }_{ i }^{ 2 } }{ 2m } ,\quad \Delta KE\quad =\frac { 144-100 }{ 2*5 } =4.4J

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