A geometry problem by Odyson Santos

Geometry Level 1

For what value of 0 ≤ x ≤ 90 0 \leq x \leq 90 is sin ⁡ x ∘ = 1 2 ? \sin x^\circ = \frac{1}{2}?


The answer is 30.

Odyson Santos by Odyson Santos , 20, Philippines

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1 solution

Mateus Gomes
Feb 12, 2016

sin ⁡ ( π 2 ± π 3 ) + 2 k π = 1 2 \sin(\frac{\pi}{2}\pm\frac{\pi}{3})+2k\pi=\frac{1}{2}

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