Where did the cosines come from?

Calculus Level 2

Let n = 0 a n \sum\limits_{n=0}^\infty a_n and n = 0 b n \sum\limits_{n=0}^\infty b_n be two convergent numerical series with positive terms.

True or false? :

The series n = 0 ( a n cos ( b n x ) + b n sin ( a n x ) ) \sum\limits_{n=0}^\infty \left(a_n\cos(b_nx)+b_n\sin(a_nx) \right) is convergent in R \mathbb{R} .

These problem is from a test by Professor Maria do Ceú.
Insufficient information True False

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1 solution

We know that n = 0 a n \sum\limits_{n=0}^\infty a_n and n = 0 b n \sum\limits_{n=0}^\infty b_n are two convergent series with positive terms, therefore the series n = 0 a n \sum\limits_{n=0}^\infty \left| a_n \right| and the series n = 0 b n \sum\limits_{n=0}^\infty \left| b_n \right| are convergent, and the series n = 0 ( a n + b n ) \sum\limits_{n=0}^\infty \left( \left| a_n \right|+\left| b_n \right| \right)
is also convergent. Let's compare the series n = 0 ( a n cos ( b n x ) + b n sin ( a n x ) ) \sum\limits_{n=0}^\infty \left( a_n\cos(b_nx)+b_n\sin(a_nx) \right) with the series n = 0 a n cos ( b n x ) + b n sin ( a n x ) \sum\limits_{n=0}^\infty \left| a_n\cos(b_nx)+b_n\sin(a_nx) \right| . We have that a n cos ( b n x ) + b n sin ( a n x ) a n cos ( b n x ) + b n sin ( a n x ) a n + b n \left| a_n\cos(b_nx)+b_n\sin(a_nx) \right| \leq \left| a_n\cos(b_nx)\right|+\left|b_n\sin(a_nx) \right| \leq\left| a_n\right|+\left|b_n \right| therefore, by a comparison test, we have that n = 0 ( a n cos ( b n x ) + b n sin ( a n x ) ) \sum\limits_{n=0}^\infty \left( a_n\cos(b_nx)+b_n\sin(a_nx) \right) converges in R \mathbb{R} .

The problem does not state that the series a n \sum a_n and b n \sum b_n are convergent; it merely states that they are "numerical series with positive terms". If they are supposed to be convergent, then the problem should say so.

Jon Haussmann - 6 years ago

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You're completely right! I've already changed the problem. Thank you!

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