Be Creative!

Let p > 3 be a prime number. How many times will a digit in p k p^k appear at least if p k p^k is a 20 digit number.


The answer is 3.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Qin Haichen
Apr 22, 2016

Suppose otherwise, which means every digit from 0-9 each repeat twice. Then the sum of digits will be = 2(0+1+2+3+4+5+6+7+8+9) = 90. 90 is divisible by 3, which can't be since p >3 and p is prime. Thus at least one digit will appear thrice.

Brilliant thinking!

Joshua Chin - 5 years, 1 month ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...