A problem by Rahul Kulkarni
Level
pending
find hight of tower PQ is hight of the tower standing on horizontal PLANE ,Qis foot of, A and B are 2 points on the plane such tat angle QAB=90 deegre AB=40M it is found tat cot angle PAQ=3/10, cot angle PBQ=1/2
FIND HIGHT OF THE TOWER
The answer is 100.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
let AQ = h
let PQ = h [height]
so, x/h = 3/10
and, sqrt(x^2+40^2)/h = 1/2
solving, h = 100