A problem by raju klatchu

Level pending

p ( 2 p ( n ) + 2016 ) p(2p(n)+2016) is divisible by 2 p ( n ) 2p(n) for n n belongs to natural numbers. Find the value of p ( 2016 ) p(2016) .

2016 1 0

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Raju Klatchu
Feb 12, 2016

let x=2p(n)+2016. therefore 2p(n)=x-2016. this implies,p(x) is divisible by x-2016. therefore by x-2016 is a factor of p(x) therefore by factor theorem,p(2016)=0

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...