An algebra problem by Rohit Kanchi

Algebra Level pending

Three articles are sold for $1,890, $2,400 and $1,135 each.The first article is sold at 12.5% profit and the second at 20% profit. If on the whole a loss of 25/8% is made, find the cost price of the third article.

$1920 $1568 $1500 $3568

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1 solution

Zee Ell
Sep 23, 2016

The 3 articles were sold for (in total):

$1890 + $2400 + $1135 = $5425

The 3 articles were bought for (total cost price):

$ 5425 ( 100 25 8 ) % = $ 5425 0.96875 = $ 5600 \frac {\$5425}{(100 - \frac{25}{8})\%} = \frac {\$5425}{0.96875} = \$5600

The first article was bought for (cost price):

$ 1890 ( 100 + 12.5 ) % = $ 1890 1.125 = $ 1680 \frac {\$1890}{(100 + 12.5)\%} = \frac {\$1890}{1.125} = \$1680

The second article was bought for (cost price):

$ 2400 ( 100 + 20 ) % = $ 2400 1.2 = $ 2000 \frac {\$2400}{(100 + 20)\%} = \frac {\$2400}{1.2} = \$2000

The third article was bought for (cost price):

$5600 - $1680 - $2000 = $1920

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