Let be positive numbers that sum to 5. The greatest possible value of can be expressed as where are integers. Find
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The strategy is to use the weighted AM-GM inequality . Assign coefficients to the variables that correspond to the exponents:
a ⇒ 3 1 b ⇒ 2 1 c ⇒ 4 1
Now weighted AM-GM inequality:
3 + 2 + 4 3 ( 3 1 a ) + 2 ( 2 1 b ) + 4 ( 4 1 c ) 3 2 a + b + c 3 1 8 5 9 2 1 0 ⋅ 3 − 1 5 ⋅ 5 9 ≥ 3 + 2 + 4 ( 3 1 a ) 3 ( 2 1 b ) 2 ( 4 1 c ) 4 ≥ 9 2 1 0 ⋅ 3 3 a 3 b 2 c 4 ≥ 2 1 0 ⋅ 3 3 a 3 b 2 c 4 ≥ a 3 b 2 c 4
Thus, the maximum is 2 1 0 ⋅ 3 − 1 5 ⋅ 5 9 , and x + y + z = 4 .