If sin x1 + sin x2 + sin x3 = 3, then find the value of cos x1 + cos x2 + cos x3.
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sin x1 + sin x2 + sin x3 = 3 when only x1=x2=x3= 90° ( because at 90° sin has a value of 1)
Now putting the values of x1, x2 & x3 in the 2nd equation we get:-
cos 90° + cos 90° + cos 90° = 0+0+0 = 0.