A geometry problem by shubham gupta

Geometry Level 3

The value of tan3A-tan2A-tanA is equal to

none of these -tan3A tan2A tanA tan3A tan2A tanA 0

Shubham Gupta by shubham gupta , 24

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1 solution

Shabarish Ch
May 27, 2014

3 A = A + 2 A 3A = A + 2A

tan ⁡ 3 A = tan ⁡ ( A + 2 A ) \tan3A = \tan(A+2A)

tan ⁡ 3 A = tan ⁡ A + tan ⁡ 2 A 1 − tan ⁡ A tan ⁡ 2 A \tan3A = \frac{\tan A + \tan2A}{1 - \tan A\tan2A}

tan ⁡ 3 A − tan ⁡ 3 A tan ⁡ 2 A tan ⁡ A = tan ⁡ A + tan ⁡ 2 A \tan3A - \tan3A\tan2A\tan A = \tan A + \tan2A

tan ⁡ 3 A − tan ⁡ 2 A − tan ⁡ A = tan ⁡ 3 A tan ⁡ 2 A tan ⁡ A \tan3A - \tan2A -\tan A = \tan3A\tan2A\tan A

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