Logarithm #3

Geometry Level 2

If log 2 ( sin π 6 ) = M \displaystyle \log _{ 2 }{ \left(\sin { \frac { \pi }{ 6 } } \right)} = -M

Then M = ? M = ?

-1 1 2 0

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1 solution

The sine 30' is 0.5 which is nothing but 2^-1. Thus, log(sin(30)) to the base 2 is log(2^-1) to the base 2 = -1*log(2) to the base 2. Hence, M=1.

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