An algebra problem by Stalin Sahoo

Assuming $x$ is a positive integer, for the RHS to be a power of two, $x$ must also be a power of two (convince yourself this is true). Obviously $x\neq2$ or $1$ but plugging in $x=4$ produces $16=16$ which is true. Thus $x=4$ . Upvote if you did this in less than or equal to half a second. :D

$\Large \log _{ 2 }{ 4x }=x \Rightarrow x=4$

$2 ^ { x } = 4x$ , the value of $x$ equals to $\log _ { 2 } 4x$ .

Then $\log _ { 2 } 4x = x$ .

We can find that $\boxed { x = \boxed { 4 } }$ easily.

All the powers of 2 are always an even number. According to the question, the number on the RHS of the equation is equal to a multiple of four which is a power of 2. Such numbers are 4, 8, 16, 32, and till infinity. By trial and error, the number which balances the equation is 16 and 16 gives us the value of x as 4 because 2^4=4*4 and thus the question is solved!!!!!!!!!!!!!!!!!!!!!

$2*2*2*2=x*x*x*x$ this is so wrong -)

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