A problem by Stuti Malik

Level 1

Given that f(x)= 3+(2x+1)^2, Find the minimum value of f(x).


The answer is 3.

Stuti Malik by Stuti Malik , 24, United Kingdom

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2 solutions

Otto Bretscher
May 7, 2015

Since we have a square, f ( x ) = 3 + ( 2 x + 1 ) 2 ≥ 3 f(x)=3+(2x+1)^2\geq{3} for all x x . Thus f ( − 1 2 ) = 3 f(-\frac{1}{2})=\boxed{3} is the minimum value.

3 Helpful 0 Interesting 0 Brilliant 0 Confused
Chinmayee Behera
May 8, 2015

3+(2x+1)^2>3 or 3+(2x+1)^2=3: minimum value of the number is 3

1 Helpful 0 Interesting 0 Brilliant 0 Confused

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