An algebra problem by surendra atti
Algebra
Level
pending
A train travels a certain distance taking 7 hours in forward journey, during the return journey increased speed 12 km/hr takes the time 5 hours. what is the total distance traveled ?
The answer is 420.
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1 solution
In 5 hours it covered 5 * 12 =60km with extra speed of 12 km/hr. It took 7 - 5= 2 hours for it to travel this distance at its first speed.. Hence its speed was 60/2 = 30 km/hr. So the distance is 30 * 7 = 210km. Total traveled = 2 * 210 = 4 2 0
OR
Let S be the forward speed. So the distance one way is, forward 7S= back 5(S+12). Therefore S=30km/hr. Total distance = 2 * 7 * S =420 km.