A probability problem by Syed Baqir

An artist is planning on mixing together any number of different colors from her palette. A mixture results as long as the artist combines at least two colors. If the number of possible mixtures is less than 500, what is the greatest number of colors the artist could have in her palette?

Assume that no two different mixtures produce the same color.

12 2 10 8

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1 solution

Shandy Rianto
Jul 8, 2015

Let n n the number of colors the artist have

The number of possible mixtures for k k colors from n n colors is ( n k ) {n \choose k}

Since a mixture needs at least two colors then then the number of possible mixtures is

( n 2 ) + ( n 3 ) + ( n 4 ) + ( n 5 ) + + ( n n ) {n \choose 2} + {n \choose 3} + {n \choose 4} + {n \choose 5} + \ldots + {n \choose n}

We have

( n 0 ) + ( n 1 ) + ( n 2 ) + ( n 3 ) + + ( n n ) = 2 n {n \choose 0} + {n \choose 1} + {n \choose 2} + {n \choose 3} + \ldots + {n \choose n} = 2^n

Since

( n 2 ) + ( n 3 ) + ( n 4 ) + ( n 5 ) + + ( n n ) < 500 {n \choose 2} + {n \choose 3} + {n \choose 4} + {n \choose 5} + \ldots + {n \choose n} < 500

2 n ( n 1 ) ( n 0 ) < 500 2^n - {n \choose 1} - {n \choose 0} < 500

2 n n 1 < 500 2^n - n - 1 < 500

2 n n < 501 2^n - n < 501

n = 8 \boxed{ n = 8 }

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