A warehouse contains 185 boxes of the same size. Each box contains at least 64 oranges and at most 89 oranges. Boxes containing the same number of ranges are stacked one on top of another in their own stack. Not all of the stacks have the same number of boxes. The largest stack has X boxes. What is the smallest possible value of X?
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89-64=25. However, since 64 can be included, we add 1, making it 26. Then divide 185 by 26, making 7 R 3. The remainder is important in this case. We could say 23 of the boxes, not including the remainder, has 7 boxes. However, since the 3 is included, we must round upward, so therefore, the answer is 8.
A simpler way of attempting the last step would be just saying 185/26=7 3/26. We would round this upward, bringing us to the solution, 8.