The meeting

Chodeldcrok is $\text{x km}$ far away from Paetoisentawa.

The distance from Chodeldcrok to Maeraippedear is $\text{441 km}$ shorter than the distance from Maeraippedear to Paetoisentawa.

A train named Inantstalstaft went from Paetoisentawa to Chodeldcrok.

After $\text{8 hours}$ , another train named Intermidmualdiatemely went from Chodeldcrok to Paetoisentawa.

They met each other at Maeraippedear then continue going.

It took $\text{20 more hours}$ for the Intermidmualdiatemely to reach Paetoisentawa.

How long did it take the Inantstalstaft to go from Maeraippedear to Chodeldcrok?

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Great! You just found out that the answer is in the form of $\dfrac{m(n_1x - p_2)(n_2x - p_2)}{(n_3x - p_3)^2}$ .

Please enter $m(n_1n_2n_3 - p_1p_2p_3)$ as your result.

$hcf(n_1;p_1) = hcf(n_2;p_2) = hcf(n_3;p_3) = 1$

This is part of the series: " It's easy, believe me! "