log in root

Algebra Level pending

If x = ( log a b ) 1 / 2 x = ( \log_a b )^{1/2} and y = ( log b a ) 1 / 2 y = (\log_b a)^{1/2} , find the value of a x b y a^x - b^y such that all the logarithms are defined.


The answer is 0.

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1 solution

Vansh Gupta
Mar 22, 2017

can anyone please provide solution to this problem

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