A problem by Vineeth O'Connor

Level pending

solve

continuous but not differentiable continuous but differentiable discontinuous none of these

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1 solution

Vineeth O'Connor
Aug 12, 2014

y^2 = 4ax implies y=+(4ax)^1/2 and y= -(4ax)^1/2 so for one value of 'x' you get two different values so this is not a function ! please do read the question properly :D and well done if you have done it correctly !

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