A geometry problem by Yellow Tomato

Geometry Level pending

Given A B = 7 \overline{AB} = 7 in A B C D \sqsubset\!\sqsupset{ ABCD} with A B C D \overline{AB} \parallel \overline{CD} . With extension of the rectangle from midpoint E on A B \overline{AB} to point G and E G = 12 \overline{EG} = 12 and E G A B \overline{EG} \bot \overline{AB} another midpoint placed on E G \overline{EG} , point F. And extension of B C \overline{BC} to point H where B H = 17 \overline{BH} = 17 Another point I, the midpoint of C D \overline{CD} . Where F I = 20 \overline{FI}=20 Find the ratio of the area of H F I : A B C D \triangle{HFI} : \sqsubset\!\sqsupset{ABCD} to the nearest hundred thousand.


The answer is 0.35714.

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