An algebra problem by Yogeshwaran K
Algebra
Level
pending
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
100kmph
120kmph
130kmph
110kmph
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1 solution
Let speed of the car be x kmph.
Then, speed of the train = 150/100 x = 3/2 x kmph. therefore, 75/x - 75/(3/2)x = 125/10 60 --> x=(24 25)/5 = 120kmph