A product of things 2

Calculus Level pending

n = 1 ( 1 n 7 + 1 n 5 + 1 n 4 + 1 n 3 + 1 n 2 + 1 ) = cosh 3 ( π b 2 ) π a \prod _{n=1}^{\infty } \left(\frac{1}{n^7}+\frac{1}{n^5}+\frac{1}{n^4}+\frac{1}{n^3}+\frac{1}{n ^2}+1\right)=\frac{\cosh ^3\left(\frac{\pi \sqrt{b}}{2}\right)}{\pi ^a}

where a , b a,b are positive integers. Submit a + b a+b .

Bonus: Let p ( x ) p(x) be a polynomial. Find a formula for

n = 1 ( p ( 1 n ) n 2 + 1 ) \prod _{n=1}^{\infty } \left(\frac{p\left(\frac{1}{n}\right)}{n^2}+1\right)

Bonus 2: Let p ( x ) p(x) and q ( x ) q(x) be polynomials with d e g ( p ) 2 + d e g ( q ) deg(p) \leq 2 + deg(q) . Find a formula for

n = 1 ( p ( x ) q ( x ) + 1 ) \prod _{n=1}^{\infty } \left(\frac{p(x)}{q(x)}+1\right)


The answer is 6.

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1 solution

Hint for Bonus: Let d d be the degree of p ( x ) p(x) . The formula involves the product of d d Gamma functions, whose arguments are the roots of a certain polynomial of degree d d .

For Bonus 2, write 1 + p ( x ) q ( x ) = P ( x ) Q ( x ) 1+\frac{p(x)}{q(x)} = \frac{P(x)}{Q(x)} . Then the product equals

roots w of Q Γ ( 1 w ) roots z of P Γ ( 1 z ) \frac{\prod_{\text{roots w of Q}} \Gamma(1-w)}{\prod_{\text{roots z of P}} \Gamma(1-z)}

(prove this)

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