A Puzzling Number
Algebra
Level
pending
There is a number which is greater than the aggregate of its third, tenth and twelfth parts by 58 .
What is the number?
The answer is 120.
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1 solution
Call the number X.
The number is larger than the sum of 1/3 X , 1/10 X and 1/12 X by 58.
X = X/3 + X/10 + X / 12 + 58
29*X/60 = 58
X = 60*58/29 = 120