A question about Penrose Euclidean plane tiling.

Geometry Level 3

This problem's question: Why is this statement about Penrose tiling : "Penrose tiling is non-periodic, which means that it lacks any translational symmetry" correct?

The square root of 5 is irrational. This is the only form of tiling that is aperiodic. This is true of all tilings. The statement is not correct.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

There are multiple types of aperiodic tilings.

There are tilings that are periodic: e.g., rectangles, triangles and hexagons.

The statement is correct. Mathematical proofs exist to support the statement.

The square root of 5 is used in the construction of the tiles' design. The aperiodicity comes from the fact that other apparent duplicates are subtly rotated from the other apparent copies by the irrational nature of the square of 5.

It is well-known that GoldenRatio, 5 1 2 \frac{\sqrt5-1}2 is pervasive throughout the construction of the regular pentagon.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...