A question of proportionality

Algebra Level 2

Let x and y be positive real numbers such that:

36:x :: x:y :: y:60

y - x is:

less than 8 greater than 8 exactly equal to 8 not enough information given to deduce

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1 solution

Denton Young
Nov 9, 2015

The ratio is ( 60 / 36 ) 1 / 3 (60/36)^{1/3} , so:

x = 36 * ( 60 / 36 ) 1 / 3 (60/36)^{1/3} = 42.683

y = 36 * ( 60 / 36 ) 2 / 3 (60/36)^{2/3} = 50.606

y - x = 7.933

Moderator note:

Is there a way to tell that it is less than 8 without having to go through the painful calculations?

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