Let's say we have a theoretical 6D cube(side length one) then which is transformed.The matrix of transformation is defined as follows.
1 2 3 4 5 6
7 8 9 10 11 12
13 14 15 16 17 18
19 20 21 22 23 24
25 26 27 28 29 30
31 32 33 34 35 36
The volume of this cube is k and the space diagonal is n .find n sqrt(k+6) Use common sense or calculator if necessary?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
You might have said that the determinant of the matrix is 0 because the integers are consecutive and that is a property of those matrixes or you calculated and also got 0.So the volume is 0 original volume which is 0.0+6 is 6.In DEFINITELY NOT A COMMON SENSE PROBLEM it is explained how to find a space diagonal of a N dimensional cube.Anyways using that technique we have sqrt 6.sqrt6 sqrt6=6.