A Sign and a Limit

Calculus Level 1

$\lim_{x\to0} \dfrac{\sin 2x}x = \, ?$

x^2

2

x

2x

1 solution

Colin Carmody
Feb 1, 2016

$\lim_{x->0} [\sin (Ax) / Bx] = \frac{A}{B}$ , the answer is $\frac{2x}{x}$ or $2$ .

Small typo: It should be $Ax$ and $Bx$ in the first expression

Otto Bretscher - 5 years, 4 months ago

Oh, I learned it without the x, but I changed it. Thanks!

Colin Carmody - 5 years, 4 months ago

It makes no sense without the $x$ .... your original version does not work if A and B are constants, for example

Otto Bretscher - 5 years, 4 months ago

We are working out limit as $x \rightarrow 0$ . If $x$ is only absent , it does not make sense.

Nihar Mahajan - 5 years, 4 months ago

Nihar Mahajan - 5 years, 4 months ago