What is the area of a triangle with vertices at ( 0 , 0 ) , ( 0 , 6 ) and ( 3 , 3 ) ?
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Simple standard approach. Sometimes it can be hard to find a suitable base and height.
By using matrix,,,,,we can do it... ⎣ ⎡ 0 0 3 0 6 3 1 1 1 ⎦ ⎤
Next step [ 0 3 6 3 ]
So →( 0 × 3 ) + ( 6 × 3 ) =0+18=18
So, the area of that triangle 0.5*18=9(Ans)
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Draw a straight line from (0, 0) to (0, 6). This is the triangle's base. It has a length of 6.
Now drop a perpendicular to this from (3, 3). It has a length of 3. This is the triangle's height.
Area of triangle = 1/2 * base * height = 1/2 * 3 * 6 = 9