A simple cha(lle)nge!

Calculus Level 4

Evaluate

lim α 0 + 0 α d θ cos ( θ ) cos ( α ) . \large \lim_{\alpha \to 0^+} \int_0^{\alpha} \dfrac{d\theta}{\sqrt{\cos(\theta) - \cos(\alpha)}}.


The answer is 2.221441469079.

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1 solution

Plinio Sd
Feb 4, 2016

First thing to do is eliminate α \alpha from the interval of integration. Let us make the following substitution: θ = α x \theta = \alpha x . Then, we have

lim α 0 + 0 1 α cos ( α x ) cos ( α ) d x . \lim_{\alpha \to 0^+} \int_0^1 \dfrac{\alpha}{\sqrt{\cos(\alpha x) - \cos(\alpha)}}dx.

Now we use the Dominated convergence theorem in order to exchange the limit with the integral. We can do so, because it is possible to bound the absolute value of the function by another integrable function, for example π 1 x 2 \frac{\pi}{\sqrt{1-x^2}} . Then, 0 1 lim α 0 + α cos ( α x ) cos ( α ) d x = 0 1 2 1 x 2 d x = 2 2 π . \begin{aligned} & \int_0^1 \lim_{\alpha \to 0^+} \dfrac{\alpha}{\sqrt{\cos(\alpha x) - \cos(\alpha)}}dx \\ = & \int_0^1 \dfrac{\sqrt{2}}{\sqrt{1-x^2}}dx \\ = & \dfrac{\sqrt{2}}{2} \pi. \end{aligned}

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