A simple eletricity problem!

The ratio of masses of two copper wire of same length are 5:3,then find the tatio of their resistances

12:37 3:5 9:25 5:3

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

From the given informations, the ratio of the cross sectional areas of the two wires is 5 : 3 5:3 . Since resistance is inversely proportional to the cross sectional area, the required ratio is 3 : 5 \boxed {3:5} .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...