A simple expansion problem

If ( a + b + c + d + e + f + g + h + i ) 2 (a+b+c+d+e+f+g+h+i)^2 is expanded and simplified, how many different terms are in the final expression?


The answer is 45.

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2 solutions

Hung Woei Neoh
May 15, 2016

When we expand this expression, we have:

a 2 + b 2 + + i 2 a^2+b^2+\ldots+i^2 , which has 9 9 terms

a b + a c + + a i ab+ac+\ldots+ai , which has 8 8 terms

b c + b d + + b i bc+bd + \ldots + bi , which has 7 7 terms (we don't add b a ba because it's the same as a b ab )

c d + c e + + c i cd+ce+ \ldots + ci , which has 6 6 terms

d e + d f + + d i de + df + \ldots + di , which has 5 5 terms

e f + e g + e h + e i ef + eg +eh +ei , which has 4 4 terms

f g + f h + f i fg+fh+fi , which has 3 3 terms

g h + g i gh+gi , which has 2 2 terms, and

h i hi , which is the final term in the expression

Total number of terms = 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45 = 9 +8 +7 +6+5+4+3+2+1 = \boxed{45}

Exactly!! Did the same . It can be generalized that square of n different terms has - n*(n+1)/2 terms in the resultant expression.

Aditya Kumar - 5 years ago

Absoluletly right!!

Puneet Pinku - 5 years, 1 month ago
Gaurav Chahar
May 14, 2016

(Combinations of 2 out of 9) plus( 9) equals 45 terms combinations of 2 out of 9 for heterogeneous products and 9 for homogeneous products.

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