A simple pendulum

Classical Mechanics Level 2

A simple pendulum set-up inside a stationary lift has a period $\large T$ . What will be its period if the lift moves upward with an acceleration $\dfrac{g}{8}?$

Note: here $g$ is considered as Gravity of Earth

and $T$ =The period of oscillation

8\times\ T

\dfrac{2\sqrt 5}{7} \times\ T

T\times\ 4

\dfrac{2\sqrt 2}{3} \times\ T

1 solution

Nazmus Sakib
Sep 20, 2017

$\large\frac {T_1}{T_2} = \sqrt \frac {g_2}{g_1}$

or, $\large{T_1 = T_2 \times\ \sqrt \frac {g_2}{g_1}}$

or, $\large{T_1= T \times\ \sqrt \frac {g}{g+\frac {g}{8}}}$

$\large=T \times\ \sqrt \frac {8}{9}$

$\large=T \times\ \sqrt \frac {4 \times\ 2}{9}$

$\large=\dfrac{2\sqrt 2}{3} \times\ T$

A simple pendulum

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