A simple pendulum

Classical Mechanics Level 3

A simple pendulum with length l l and bob of mass m m execute S H M SHM of small amplitude A A . The maximum tension in the string will be

m g ( 1 + ( A l ) 2 ) mg(1+(\frac{A}{l})^{2}) m g mg m g ( 1 + A l ) mg(1+\frac{A}{l}) N o n e None m g ( 1 + A l ) 2 mg(1+\frac{A}{l})^{2} 2 m g 2mg

Tanishq Varshney by Tanishq Varshney , 23, India

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1 solution

Vijay Simha
Oct 26, 2017

Tmax = mg + m*v^2/l

At the mean position,

Let omega be the angular frequency of the pendulum

v = a*omega, omega = sqrt(g/l)

Tmax = mg + (m/l) a^2 g/l

Tmax = mg(1 + a^2/l^2)

3 Helpful 0 Interesting 0 Brilliant 1 Confused

What’s the A supposed to be? I’m confused

Rohan Joshi - 4 months ago

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A is the Amplitude.

Vijay Simha - 3 months, 3 weeks ago

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yeah but what amplitude? maximum angular displacement or max height

Rohan Joshi - 3 months, 3 weeks ago

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