A simple trigonometry problem

Geometry Level 2

Find the value of 12 s i n 2 6 1 0 + 8 + 12 s i n 2 2 9 0 9 c o s 2 1 3 0 + 1 + 9 c o s 2 7 7 0 \frac{12sin^{2} 61^{0} + 8 + 12sin^{2} 29^{0}}{9cos^{2} 13^{0} + 1 + 9cos^{2} 77^{0}} .

3 4 1 2

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Manish Mayank
Nov 29, 2014

12 s i n 2 6 1 0 + 8 + 12 s i n 2 2 9 0 9 c o s 2 1 3 0 + 1 + 9 c o s 2 7 7 0 \frac{12sin^{2} 61^{0} + 8 + 12sin^{2} 29^{0}}{9cos^{2} 13^{0} + 1 + 9cos^{2} 77^{0}} = 12 s i n 2 6 1 0 + 8 + 12 c o s 2 6 1 0 9 s i n 2 7 7 0 + 1 + 9 c o s 2 7 7 0 \frac{12sin^{2} 61^{0} + 8 + 12cos^{2} 61^{0}}{9sin^{2} 77^{0} + 1 + 9cos^{2} 77^{0}} = 12 ( s i n 2 6 1 0 + c o s 2 6 1 0 ) + 8 9 ( s i n 2 7 7 0 + c o s 2 7 7 0 ) + 1 \frac{12(sin^{2}61^{0} + cos^{2}61^{0}) + 8}{9(sin^{2}77^{0} + cos^{2}77^{0}) + 1} = 12 + 8 9 + 1 \frac{12+8}{9+1} = 20 10 \frac{20}{10} = 2 \boxed{2}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...