A solid problem

Volume of the base $=π\times 14^2\times 7=4312$ c. c. assuming the value of $π$ to be $\dfrac {22}{7}$ .

Height of side wall is $10-7=3$ cm. So it's volume is $π\times (14^2-7^2)\times 3=1386$ c. c.

So the volume of the material of the container is $4312+1386=\boxed {5698}$ c. c.

First method: The glass can be broken into a hollow cylinder (of internal radius 7cm ,external radius 14cm and height 10 cm ) and a solid cylinder (of radius 7cm and height 7cm).Intution behind it,if you think about a glass we can cut out it into a hollow cylinder by pushing its base outside and since width remains every where so, height comes out 7cm(R-r=14-7)....now the total volume of glass comes out volume of hollow cylinder + volume of solid base = 4620+1078=5698 cubic centimetre.......... Second method: The glass can be broken into a hollow cylinder (of internal radius 7cm ,external radius 14cm and height 3cm[10-(R-r)] ) and a solid cylinder (of radius 14cm and height 7cm).Intution behind it you can cut out solid base from glass So,volume of glass= volume of hollow cylinder+ solid base=4312+1386=5698...end game