A special dice with numbers on its faces is thrown thrice then find the number of ways such that the sum of numbers appeared on faces is equal to
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2 1 − 3 = 6 2 0 − 2 = 6 2 − 1 − 1 = 3 1 1 − 2 = 3 1 0 − 1 = 6 0 0 0 = 1 = 2 5