In a square with side 32, two-quarter circles are drawn. Another smaller circle is drawn such that it is tangent to the quarter circles and the square. What is the radius of the smaller circle?
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Say the radius of the circle is r and its centre C . Let A be one of the vertices of the bottom edge of the square and M its midpoint, so Δ A M C is a right-angled triangle:
We have A M = 1 6 , A C = 3 2 + r and M C = 3 2 − r ; so by Pythagoras, A C 2 − M C 2 ( 3 2 + r ) 2 − ( 3 2 − r ) 2 6 4 ⋅ 2 r r = A M 2 = 1 6 2 = 2 5 6 = 2