A Straight Forward L.C.M.

Number Theory Level 2

$\huge \color{#D61F06}{1}, \color{#20A900}{\pi}$

Find the lowest common multiple (L.C.M.) of the given above two numbers ?

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\pi

1 L.C.M. does not exist None of the above.

1 solution

Abhishek Sharma
May 8, 2015

If LCM of $a$ and $b$ is $L$ , then $L=a\times n=b\times m$ where $n$ and $m$ are integers.

Now if LCM of $1$ and $\pi$ exists then $e=\frac{n}{m}$ . But this can't be true as $\pi$ is an irrational number and $\frac{n}{m}$ is rational. Our assumption was wrong therefore LCM of $1$ and $\pi$ does not exist.

Great reasoning!

Yoogottam Khandelwal - 5 years, 11 months ago

A Straight Forward L.C.M.

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1 solution

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