A Strange Solid

Level pending

A solid has a circular base with radius 1. 1. Parallel cross-sections perpendicular to the base are equilateral triangles.

The volume of the solid can be represented by A B C , \dfrac{A\sqrt{B}}{C}\text{,} where A A and C C are positive coprime integers and B B is square-free. What is A + B + C ? A+B+C\text{ ?}


The answer is 10.

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1 solution

Mandar Sohoni
Feb 27, 2014

The base is a circle with radius r, now consider a sliver of the circle at distance x from the center of the circle (to the right or to the left, it doesn't matter) of width dx. The length of the sliver is r 2 x 2 \sqrt{r^{2} - x^{2}} . This is also the base of the equilateral triangle. The volume of this triangle = d V = 3 × ( r 2 x 2 ) × d x = dV = \sqrt{3} \times (r^{2} - x^{2}) \times dx . Integrating from 0 to r, we get V = 2 3 × 3 × r 3 V = \frac{2}{3} \times \sqrt{3} \times r^{3} . However this is only half the volume. The total volume = 4 3 × 3 = \frac{4}{3} \times \sqrt{3} thus, A + B + C = 10 A+B+C = 10

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