A solid has a circular base with radius Parallel cross-sections perpendicular to the base are equilateral triangles.
The volume of the solid can be represented by where and are positive coprime integers and is square-free. What is
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The base is a circle with radius r, now consider a sliver of the circle at distance x from the center of the circle (to the right or to the left, it doesn't matter) of width dx. The length of the sliver is r 2 − x 2 . This is also the base of the equilateral triangle. The volume of this triangle = d V = 3 × ( r 2 − x 2 ) × d x . Integrating from 0 to r, we get V = 3 2 × 3 × r 3 . However this is only half the volume. The total volume = 3 4 × 3 thus, A + B + C = 1 0