A sum of odd integers

Algebra Level 1

Evaluate

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19. 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19.


The answer is 100.

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9 solutions

(1+19)+(3+17)+...+(9+11)=20x5=100

Moderator note:

Nice approach, realizing that the pairs of numbers taken from the end all add up to 20.

keke mana ni

Cicak Dinding - 7 years, 10 months ago

[(l+1)/2]^2 where 'l' is the last odd number in the sequence

Hari Kumar - 7 years, 10 months ago

1+3+5+7+9+11+13+15+17+19 =(1+19)+(3+17)+(5+15)+(7+13)+(9+11) =20+20+20+20+20 =100

Girija Lenka
Aug 3, 2013

{20 x 10} = 200 as there are 10 numbers so the answer will be 200/2 = 100

great job

thirumeny santhoshsivan - 7 years, 10 months ago
Caio Gonçalves
Jul 31, 2013

As somas dos elementos das extremidades, ou seja, os elementos os quais os 5 primeiros números iniciais se relacionam, ambos correpsondem a uma soma de resultado igual a 20. Multiplicado 20 pelas cinco pares que podem ser feitos, encontramos o valor final de 100.

1+19=3+17=5+15=7+13=9+11=20 so 20*5=100

great bro

thirumeny santhoshsivan - 7 years, 10 months ago
Ellimrac Leee
Jul 30, 2013

Just add them all :)

Matheus Pinto
Jul 29, 2013

1+3+5+7+9+11+13+15+17+19=100

Também poderia ser calculado utilizando a formula da Soma de uma PA

Sn = a11+an . n / 2

S10= (1 + 19) . 2 / 2 = 100

Thauan Vieira de Barcellos - 7 years, 10 months ago

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Sim, correto.

Matheus Pinto - 7 years, 10 months ago
Souperman Arcena
Jul 29, 2013

1st and 10th number total is 20 which is applicable to 2nd to 9th,3rd to 8th and so on so 20 x 5= 100

Yan Jie Chong
Jul 28, 2013

9 + 13 = 22 22/2 = 11

(9 * 11) + 1 = 100

100

Djsrabon Srabon - 7 years, 10 months ago

any increment sequence starts with {a} and has a step {d} can be written as a , a+d , a+2d , a+3d , a+4d ,
for our sequence here to get the i-th element we follow {element (i)= 1 + (i-1) 2 } and its summation follow { S(i)= i 1+ ( ( i )* (i-1) / 2) * 2 ) } putting i =10 , S(10)=10 + 90 =100

Amr Eldfrawy - 7 years, 10 months ago

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