A Tank

Let the capacity of the water be 'x' Then 1/3(x)+200= 1/2(x) If so 200= 1/2(x)-1/3(x)= 1/6(x)

So x= 200*6= 1200 liters

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Let $t = Capacity$

From the question we can get the equation

$\frac {t}{3} + 200 = \frac {t}{2}$

Re-arranging it gives us

$200 = \frac {t}{6}$

So

$t = 200 \cdot 6 = 1200$

The capacity of the tank is $1200$ liters

The difference of a third and a half is a sixth. If I sum third plus sixth I get a half. Knowing this we can make a little calculus.....

if 200 is a sixth a integer is 200*6 equals 1200.

suppose total capacity of water is V liters; then (V/30)+200 = (V/2) ; V=1200 liters

1/3 volume becomes 1/2 when 200 liters of water is added.i.e. 1/2--1/3 =1/6 =200 lts. Therefore, 1 full tank = 6x200= 1200 lts.

Let capacity is X liters, when 1/3 filled it is X/3, now add 200 lits it becomes X/2 So equation is X/3 + 200 = X/2 ,by solving we get value of x =1200 Litas Ans

K.K.GARG,India

1/3 x + 200 = 1/2 x where x is the total volume

(x/3) + 200=(x/2). Resolving, we find (x/6)=200 then => x=1200L

x/3=400 ; x=1.200 L

1/3(X) + 200 = 1/2(X). Therefore, 1/6(X) = 200, so X = 200 x 6 = 1200.

1/3a+200=1/2a -> a=1/6. 200= 1200