A tortoise and a hare race

A tortoise and a hare race against each other. A hare runs at a constant speed of 36 km per hour for exactly ten seconds and waits for the tortoise to catch up. If the tortoise takes two hours to move 1 km, how long will it take in minutes to catch up?


The answer is 12.

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1 solution

Norhan Mahmoud
Nov 21, 2014

First of all to facilitate our calculations, we should know both the hare's and tortoise's speed in terms of m/sec and that can be done as follows: hare's speed= 36 × 1000 / 6 0 2 = 10 m / s e c 36 \times 1000/60^2 =10 m/sec tortoise's speed= 0.5 × 1000 / 6 0 2 = 5 36 m / s e c 0.5 \times 1000/60^2 = \frac{5} {36} m/sec Now, by multiplying the hare's speed to the time it took to move, we'll deduce that it moved 100 metres. To know how long the tortoise took in order to move this distance, you'll divide the distance 100 m 100m by the tortoise's speed 5 36 m / s e c \frac{5}{36} m/sec and we'll deduce that it'll take 720 seconds to catch up with the hare, which equals 12 \boxed{12 } minutes.

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