A train Problem
A train and a morning walker leave their respective places at the same time and travel in opposite directions. They meet each other at a fixed place and fixed time. The speed of the train is 60 km/h and the speed of the morning walker is 5 km/h One day, the train is late. The morning walker has to travel 5 km extra to meet the train. By how many minutes is the train late ?
The answer is 65.
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1 solution
If the morning walker has to travel 5 km extra, he will take 60 minutes. But the train will take 5 min more to reach the usual meeting spot. So, the answer is 60 + 5 = 65.