A tribute to Indian Morning Prayers in Schools.
There are 234 boys and 286 girls in a school. All the students gather in the ground at the morning time for the Morning Prayer and stand/sit in queues (maintaining discipline).
In how many minimum rows all the students can stand/sit so that every row contains either only boys or only girls such that each row consists of equal number of students?
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1 solution
Maximum no. of students needed to be stood/sit in a row so that all the students can stand/sit occupying minimum no. of rows= g c d ( 2 3 4 , 2 8 6 ) = 2 6
Therefore,
Minimum no. of rows in which all boys will stand/sit = 2 3 4 / 2 6 = 9
Minimum no. of rows in which all girls will stand/sit = 2 8 6 / 2 6 = 1 1
Hence Minimum no. of rows= 9 + 1 1 = 2 0 .
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