A Tricky Math Puzzle

One dog = 1 bone/6 minutes, therefore 100 dogs = 100 bones/6 minutes. The answer is:

$6$ minutes

6 D find 6 B in 6 Min | 1 D find 1 B in 6 Min | 100 D find 100 B in 6 Min | Easy :)

Think of letting each dog finding a single bone. Since each dog does not rely on the other, each of them will find a bone in 6 minutes. No matter, if there were 100 dogs or 1000 dogs

For this particular problem, $\dfrac{x \cdot \text{Dogs}}{x \cdot \text{Bones}} = 6 \text{ minutes}$

We are told it takes 6 minutes for 6 dogs to find 6 bones. Thus, it takes 6 dog-minutes to find one bone.

So, $(100 \textrm{ bones}) * \frac{6 \textrm{ dog-minutes}} {\textrm{bone}} * (\frac{1}{100 \textrm{ dogs}}) = 6 \textrm{ minutes}.$

1 dog can find a bone in 6 mins.

So 100 dogs can find 100 bones in 6 mins