Is it a Projectile?

A smooth cylindrical log of wood of radius R meter is fixed on a horizontal surface. The minimum speed with which a particle should be projected to reach other side is xgR \sqrt{\text{xgR}} where g is acceleration due to gravity. Find x.

Try more from my set Classical Mechanics Problems .


The answer is 4.

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2 solutions

For the particle to reach the other side it should cross the top of the log with minimum possible speed.

Now just think reversely. What will happen if someone at the top of log gently disturb a particle?

At some point on the log, the particle will leave and start doing projectile motion and it hits the ground at some point with speed 4 g R \sqrt{4gR} and at some angle with horizontal.

Now if we throw a particle with same speed, at same angle from horizontal and from the same point on the ground, it will retraces its previous path and reach the top of the log.

And if the speed is just greater than 4 g R \sqrt{4gR} , the particle will go to the top of the log with some velocity and finally reach the other end.

Overrated. Btw Nice solution .

Keshav Tiwari - 6 years, 4 months ago

I think it should be somewhat better stated like a pipe and not a log of wood ?! their a certainly some difference in them....

Saurabh Patil - 6 years, 1 month ago

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The only thing which matters is that it is cylindrical either it be log or a pipe.

Purushottam Abhisheikh - 6 years, 1 month ago

How you got 4 , please can you elaborate more.

Syed Baqir - 5 years, 11 months ago

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Use conservation of mechanical energy. I hope this will help you.

Purushottam Abhisheikh - 5 years, 11 months ago

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Thank you .

Syed Baqir - 5 years, 11 months ago
Yashit Garg
Feb 23, 2015

Energy conservation Method: particle will just touch the top with zero vertical speed so applying energy conservation 0.5.m.v^2 = m.g.2R so v=root(4gR)

Why vertical height is 2R, please can you add more information ?

Syed Baqir - 5 years, 11 months ago

actually answer of this question is x=2+2*2^0.5

gaurav gupta - 4 years ago

mistake in your solution is that is at highest point vertical velocity is zero then how can it is covering a non zero range???

gaurav gupta - 4 years ago

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