A Trigonometric problem for JEE Aspirants

Geometry Level 4

E = tan ( A ) tan ( 2 A ) + tan ( 2 A ) tan ( 4 A ) + tan ( 4 A ) tan ( A ) E = \tan(A) \tan(2A) + \tan(2A) \tan(4A) + \tan(4A) \tan(A)

Find the value of E E where A = 2 π 7 A = \dfrac{2\pi}7 .


This is Original.
Also try Range of a Three Variable Function .


The answer is -7.

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2 solutions

Anupam Khandelwal
Sep 23, 2015

Aakash Khandelwal
Oct 16, 2015

Apply : cyclic sum of tangents of angles of a triangle taken two at a time = 1+1/product of cosines

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